Math Lab

Inverse Trig: y = a · arcsin(b x)

Inverse Trigonometric Functions · Class XII

Domain of arcsin is [-1, 1]. Scale x with b and watch where the curve is defined.

1
type a value
-33
1
type a value
0.13
Live values
  • Domain1
  • Range1.5708
  • y at x = 1/(2b)0.5236
xy
  • y = a · arcsin(b x)

Formulas in this lab

  • Domain
    x∈[−1/b, 1/b]x \in [-1/b,\,1/b]
  • Range
    [−aπ/2, aπ/2][-a\pi/2,\,a\pi/2]
  • y at x = 1/(2b)
    a⋅π/6a \cdot \pi/6
Tip: Outside |b x| ≤ 1 arcsin is undefined , the curve simply stops.

Frequently asked questions

▶What are the principal-value domains of $\sin^{-1}$, $\cos^{-1}$ and $\tan^{-1}$?

$\sin^{-1}: [-1, 1] \to [-\pi/2, \pi/2]$. $\cos^{-1}: [-1, 1] \to [0, \pi]$. $\tan^{-1}: \mathbb{R} \to (-\pi/2, \pi/2)$. These restricted ranges make the inverses single-valued functions, not relations.

▶How do I use the inverse trig domains lab?

Slide an input $x$ and the lab returns $\sin^{-1}(x)$, $\cos^{-1}(x)$ and $\tan^{-1}(x)$ in radians and degrees, plus the identity $\sin^{-1}(x) + \cos^{-1}(x) = \pi/2$. Try $x = 0.5$ to see $\sin^{-1}(0.5) = \pi/6$ and $\cos^{-1}(0.5) = \pi/3$.

▶Why does $\sin^{-1}(\sin(2\pi)) = 0$ and not $2\pi$?

Because $\sin^{-1}$ only outputs values in $[-\pi/2, \pi/2]$, and $\sin(2\pi) = 0$, so the inverse returns $0$. Students often write $2\pi$ and lose marks. The composition rule is $\sin^{-1}(\sin\theta) = \theta$ only when $\theta\in[-\pi/2, \pi/2]$.

▶Where does $\tan^{-1}$ appear in real applications?

Computing the angle of elevation: if a kite is at height $h$ and horizontal distance $d$, angle is $\theta = \tan^{-1}(h/d)$. Smartphone level apps, drone tilt sensors, and the autopilot in commercial aircraft all use the inverse tangent to recover angles from ratios.

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