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Chapter 7: Integrals

Integration is the reverse process of differentiation. If ddxF(x)=f(x)\dfrac{d}{dx}F(x) = f(x), then FF is an antiderivative of ff, and we write ∫f(x) dx=F(x)+C\int f(x)\,dx = F(x) + C. The constant of integration CC captures the fact that infinitely many functions share the same derivative , they differ only by a constant. This single insight powers a vast machinery: from finding the area under a curve to computing work done by a variable force, from solving differential equations in physics to evaluating probabilities in continuous distributions.

Two integrals live in this chapter. The indefinite integral ∫f(x) dx\int f(x)\,dx produces a family of functions. The definite integral ∫abf(x) dx\int_a^b f(x)\,dx produces a number , interpreted geometrically as signed area between the curve y=f(x)y = f(x) and the xx-axis on [a,b][a, b]. The two are stitched together by the Fundamental Theorem of Calculus: ∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx = F(b) - F(a), where FF is any antiderivative of ff. This theorem is the deepest result in elementary calculus.

For board examinations the chapter is a calculation marathon. You must memorise standard integrals (logs, exponentials, trigonometric, inverse-trigonometric forms), recognise when to substitute, when to integrate by parts, and when to decompose into partial fractions. The LIATE rule, the ex[f(x)+f′(x)]e^x[f(x)+f'(x)] pattern, and the trigonometric substitutions are tools that come back repeatedly.

For JEE the difficulty climbs. You will see integrals where the substitution is non-obvious, integrands involving ax2+bx+c\sqrt{ax^2+bx+c}, and definite integrals whose evaluation hinges on a symmetry property. Properties like ∫0af(x) dx=∫0af(a−x) dx\int_0^a f(x)\,dx = \int_0^a f(a-x)\,dx unlock problems that look impossible by direct antidifferentiation.

The prerequisites are differentiation rules from Chapter 5 and a comfort with algebraic manipulation. You must know the derivative of every elementary function instinctively , those derivatives, read backwards, are the standard integrals.

A word on aesthetics: integration is an art. Unlike differentiation (which has a deterministic algorithm), integration requires recognition. Two integrals that look similar may need very different techniques. The only way to develop the instinct is sustained practice , there is no shortcut.

What's inside

  1. Indefinite integrals and standard forms , antiderivatives, table of standards.
  2. Integration by substitution , uu-substitution and trigonometric substitution.
  3. Integration by parts , LIATE, ∫ex[f+f′] dx\int e^x[f+f']\,dx trick.
  4. Partial fractions , decomposing rational functions.
  5. Definite integral as a limit of a sum , the Riemann definition.
  6. Fundamental Theorem of Calculus , evaluation via antiderivatives.
  7. Properties of definite integrals , symmetry, additivity, king's rule.
  8. Special integrals , ∫dxx2±a2\int\frac{dx}{x^2 \pm a^2}, ∫a2−x2 dx\int\sqrt{a^2 - x^2}\,dx family.

Key results / Formula card

IntegralResult
∫xn dx\int x^n\,dxxn+1n+1+C\frac{x^{n+1}}{n+1} + C, n≠−1n \neq -1
∫1x dx\int \frac{1}{x}\,dx$\ln
∫ex dx\int e^x\,dxex+Ce^x + C
∫sin⁡x dx\int \sin x\,dx−cos⁡x+C-\cos x + C
∫cos⁡x dx\int \cos x\,dxsin⁡x+C\sin x + C
∫sec⁡2x dx\int \sec^2 x\,dxtan⁡x+C\tan x + C
∫dx1+x2\int \frac{dx}{1+x^2}tan⁡−1x+C\tan^{-1} x + C
∫dx1−x2\int \frac{dx}{\sqrt{1-x^2}}sin⁡−1x+C\sin^{-1} x + C
∫dxx2−a2\int \frac{dx}{x^2-a^2}$\frac{1}{2a}\ln\left
∫dxx2+a2\int \frac{dx}{x^2+a^2}1atan⁡−1(x/a)+C\frac{1}{a}\tan^{-1}(x/a) + C
∫a2−x2 dx\int \sqrt{a^2-x^2}\,dxx2a2−x2+a22sin⁡−1(x/a)+C\frac{x}{2}\sqrt{a^2-x^2} + \frac{a^2}{2}\sin^{-1}(x/a) + C
By parts∫u dv=uv−∫v du\int u\,dv = uv - \int v\,du
FTC∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx = F(b) - F(a)
King's rule∫0af(x) dx=∫0af(a−x) dx\int_0^a f(x)\,dx = \int_0^a f(a-x)\,dx

How to read this chapter

Memorise the standard table cold. Then practise recognition: which technique fits which integral? Build a personal mental flowchart , see ln⁡x\ln x or tan⁡−1x\tan^{-1}x? Try by parts. See a rational function? Try partial fractions. See a2−x2\sqrt{a^2 - x^2}? Try x=asin⁡θx = a\sin\theta. The chapter rewards pattern recognition above all.

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