Math Lab
Home/Class XI/Ch 12/Standard limits: trigonometric, exponential, and the number e

Standard limits

A handful of standard limits appear over and over. Memorise them; recognise them in problems; reduce harder limits to them by algebraic manipulation.

The trig limits

(L1) lim⁡x→0sin⁡xx=1.\displaystyle \lim_{x \to 0} \frac{\sin x}{x} = 1.

(Here xx is in radians.) This is the most important limit in elementary calculus. Geometric argument: in a unit circle, for small x>0x > 0, the arc length xx, the chord sin⁡x\sin x, and the tangent tan⁡x\tan x satisfy sin⁡x<x<tan⁡x\sin x < x < \tan x. Divide by sin⁡x\sin x: 1<x/sin⁡x<1/cos⁡x1 < x/\sin x < 1/\cos x. As x→0x \to 0, 1/cos⁡x→11/\cos x \to 1, so x/sin⁡x→1x/\sin x \to 1, hence sin⁡x/x→1\sin x / x \to 1.

(L2) lim⁡x→01−cos⁡xx2=12.\displaystyle \lim_{x \to 0} \frac{1 - \cos x}{x^2} = \frac{1}{2}.

Derive from L1: 1−cos⁡xx2=2sin⁡2(x/2)x2=12(sin⁡(x/2)x/2)2→12\dfrac{1 - \cos x}{x^2} = \dfrac{2 \sin^2(x/2)}{x^2} = \dfrac{1}{2}\left(\dfrac{\sin(x/2)}{x/2}\right)^2 \to \dfrac{1}{2}.

(L3) lim⁡x→0tan⁡xx=1.\displaystyle \lim_{x \to 0} \frac{\tan x}{x} = 1. (Combine L1 and cos⁡x→1\cos x \to 1.)

The exponential / logarithmic limits

(L4) lim⁡x→0ex−1x=1.\displaystyle \lim_{x \to 0} \frac{e^x - 1}{x} = 1.

(L5) lim⁡x→0ax−1x=ln⁡a\displaystyle \lim_{x \to 0} \frac{a^x - 1}{x} = \ln a, for any a>0a > 0. (Use a=eln⁡aa = e^{\ln a}.)

(L6) lim⁡x→0ln⁡(1+x)x=1.\displaystyle \lim_{x \to 0} \frac{\ln(1 + x)}{x} = 1.

(L7) lim⁡x→0(1+x)1/x=e≈2.71828…\displaystyle \lim_{x \to 0} (1 + x)^{1/x} = e \approx 2.71828\dots

This is one definition of the number ee. Equivalently, lim⁡n→∞(1+1n)n=e\lim_{n \to \infty}\left(1 + \dfrac{1}{n}\right)^n = e.

The polynomial limit

(L8) lim⁡x→axn−anx−a=nan−1.\displaystyle \lim_{x \to a} \frac{x^n - a^n}{x - a} = n a^{n - 1}.

This is the basic limit for differentiating xnx^n.

Strategy: recognise and reduce

When you see a limit with sin⁡\sin, cos⁡\cos, exe^x, axa^x, or ln⁡\ln, look for one of L1–L7. Manipulate the expression , by factoring, substitution, or multiplying numerator and denominator by a clever expression , to expose the standard form.

Worked examples

Example 1. lim⁡x→0sin⁡3xx\lim_{x \to 0} \dfrac{\sin 3 x}{x}.

Write sin⁡3xx=3⋅sin⁡3x3x\dfrac{\sin 3x}{x} = 3 \cdot \dfrac{\sin 3 x}{3 x}. Let u=3xu = 3 x; as x→0x \to 0, u→0u \to 0. Limit = 3⋅1=33 \cdot 1 = 3.

Example 2. lim⁡x→0sin⁡5xsin⁡7x\lim_{x \to 0} \dfrac{\sin 5 x}{\sin 7 x}.

sin⁡5xsin⁡7x=sin⁡5x/(5x)sin⁡7x/(7x)⋅5x7x=sin⁡5x/(5x)sin⁡7x/(7x)⋅57→11⋅57=57\dfrac{\sin 5x}{\sin 7 x} = \dfrac{\sin 5x / (5 x)}{\sin 7 x / (7 x)} \cdot \dfrac{5 x}{7 x} = \dfrac{\sin 5x/(5x)}{\sin 7x/(7x)} \cdot \dfrac{5}{7} \to \dfrac{1}{1} \cdot \dfrac{5}{7} = \dfrac{5}{7}.

Example 3. lim⁡x→01−cos⁡2xx2\lim_{x \to 0} \dfrac{1 - \cos 2 x}{x^2}.

1−cos⁡2xx2=2sin⁡2xx2=2(sin⁡xx)2→2\dfrac{1 - \cos 2 x}{x^2} = \dfrac{2 \sin^2 x}{x^2} = 2 \left(\dfrac{\sin x}{x}\right)^2 \to 2.

Example 4. lim⁡x→0e2x−1x\lim_{x \to 0} \dfrac{e^{2 x} - 1}{x}.

e2x−1x=2⋅e2x−12x→2⋅1=2\dfrac{e^{2 x} - 1}{x} = 2 \cdot \dfrac{e^{2 x} - 1}{2 x} \to 2 \cdot 1 = 2.

Example 5. lim⁡x→0ln⁡(1+3x)x\lim_{x \to 0} \dfrac{\ln(1 + 3 x)}{x}.

ln⁡(1+3x)x=3⋅ln⁡(1+3x)3x→3⋅1=3\dfrac{\ln(1 + 3 x)}{x} = 3 \cdot \dfrac{\ln(1 + 3 x)}{3 x} \to 3 \cdot 1 = 3.

Try it yourself

  1. lim⁡x→0sin⁡7xx\lim_{x \to 0} \dfrac{\sin 7 x}{x}.
  2. lim⁡x→0sin⁡2xsin⁡3x\lim_{x \to 0} \dfrac{\sin 2 x}{\sin 3 x}.
  3. lim⁡x→0tan⁡3xx\lim_{x \to 0} \dfrac{\tan 3 x}{x}.
  4. lim⁡x→01−cos⁡3xx2\lim_{x \to 0} \dfrac{1 - \cos 3 x}{x^2}.
  5. lim⁡x→0e3x−12x\lim_{x \to 0} \dfrac{e^{3 x} - 1}{2 x}.
  6. lim⁡x→05x−1x\lim_{x \to 0} \dfrac{5^x - 1}{x}.
  7. lim⁡x→0ln⁡(1+5x)2x\lim_{x \to 0} \dfrac{\ln(1 + 5 x)}{2 x}.
  8. lim⁡x→0sin⁡x−tan⁡xx3\lim_{x \to 0} \dfrac{\sin x - \tan x}{x^3}. (Hint: sin⁡x−tan⁡x=−sin⁡x(1−cos⁡x)/cos⁡x\sin x - \tan x = -\sin x (1 - \cos x)/\cos x.)
  9. lim⁡x→0sin⁡x2x\lim_{x \to 0} \dfrac{\sin x^2}{x}.
  10. lim⁡x→ax3−a3x−a\lim_{x \to a} \dfrac{x^3 - a^3}{x - a}.
  11. lim⁡x→0tan⁡x−sin⁡xx3\lim_{x \to 0} \dfrac{\tan x - \sin x}{x^3}.
  12. lim⁡n→∞(1+2n)n\lim_{n \to \infty}\left(1 + \dfrac{2}{n}\right)^n. (Hint: write as ((1+2/n)n/2)2→e2((1 + 2/n)^{n/2})^2 \to e^2.)

Pitfalls / Tricks

  • xx in sin⁡x/x\sin x / x etc. must be in radians.
  • When numerator and denominator both go to 00, force one of the standard forms (e.g., sin⁡(ax)/x=a⋅sin⁡(ax)/(ax)\sin (ax)/x = a \cdot \sin(ax)/(ax)).
  • For (1+f(x))g(x)(1 + f(x))^{g(x)} with f(x)→0f(x) \to 0 and g(x)→∞g(x) \to \infty, often write as eg(x)ln⁡(1+f(x))e^{g(x) \ln(1 + f(x))} and use L6.
  • Insight. Standard limits are the vocabulary of calculus. Once you spot them, almost every 0/00/0 problem opens up.

Test Your Knowledge

Quick MCQ check on this chapter

Start Quiz →

AI Summary

Summarize this page in your favorite LLM