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Sections of a cone , the four conics

Take an infinite double cone , two cones joined at their tips, opening up and down. Slice it with a plane. Depending on the angle of the plane relative to the cone's axis, the cross-section is one of four shapes:

  1. Plane perpendicular to the axis: a circle.
  2. Plane tilted but cutting only one nappe: an ellipse.
  3. Plane parallel to a generator (a line drawn on the cone's surface): a parabola.
  4. Plane cutting both nappes: a hyperbola (two branches).

These four curves are collectively called conic sections.

The focus-directrix definition

Beyond the cone-slicing definition, every (non-circular) conic admits a beautiful unified description.

Definition. Given a point FF (the focus) and a line \ell (the directrix) not passing through FF, a conic is the set of points PP such that PFd(P,)=e,\frac{|PF|}{d(P, \ell)} = e, where e0e \ge 0 is a constant called the eccentricity.

  • 0<e<10 < e < 1: ellipse (closed curve, bounded).
  • e=1e = 1: parabola (open curve, one branch).
  • e>1e > 1: hyperbola (two branches, open).
  • e=0e = 0: circle (degenerate limiting case , focus is the centre, directrix at infinity).

The eccentricity measures how "non-circular" the conic is. A circle has e=0e = 0; a very elongated ellipse has ee close to 11; a parabola has e=1e = 1 exactly; hyperbolas have e>1e > 1.

Standard placements

For tractable algebra, we place each conic so that its axis of symmetry lies along the xx-axis (or yy-axis) and its centre (or vertex) is at the origin.

ConicStandard formEccentricity
Circlex2+y2=r2x^2 + y^2 = r^200
Parabolay2=4axy^2 = 4 a x11
Ellipsex2a2+y2b2=1\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1 (a>ba > b)1b2/a2\sqrt{1 - b^2/a^2}
Hyperbolax2a2y2b2=1\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 11+b2/a2\sqrt{1 + b^2/a^2}

Why conics matter , the physics

  • Planetary orbits. Kepler's first law (1609): planets move in ellipses with the Sun at one focus.
  • Projectiles. Neglecting air resistance, any projectile travels along a parabola.
  • Satellite dishes & headlights. A paraboloid (3D parabola) reflects parallel rays through its focus.
  • Cooling towers. Many use a hyperboloid shape for structural strength.

So the four conics are everywhere in physics and engineering, not just on JEE papers.

Worked examples

Example 1. A point moves so that its distance from (1,0)(1, 0) equals its distance from the line x=1x = -1. What curve does it trace?

Distance from (1,0)(1, 0): (x1)2+y2\sqrt{(x - 1)^2 + y^2}. Distance from x=1x = -1: x+1|x + 1|. Set equal, square: (x1)2+y2=(x+1)2y2=4x(x - 1)^2 + y^2 = (x + 1)^2 \Rightarrow y^2 = 4 x. A parabola.

Example 2. Find the eccentricity of x225+y29=1\dfrac{x^2}{25} + \dfrac{y^2}{9} = 1.

a2=25,b2=9a^2 = 25, b^2 = 9, c2=a2b2=16,c=4c^2 = a^2 - b^2 = 16, c = 4. So e=c/a=4/5e = c/a = 4/5. Ellipse.

Example 3. What kind of conic is 4x2+9y2=364 x^2 + 9 y^2 = 36?

Divide by 3636: x29+y24=1\dfrac{x^2}{9} + \dfrac{y^2}{4} = 1. Ellipse with a2=9,b2=4a^2 = 9, b^2 = 4.

Example 4. Identify x2y2=16x^2 - y^2 = 16.

x216y216=1\dfrac{x^2}{16} - \dfrac{y^2}{16} = 1. Hyperbola with a=b=4a = b = 4. Asymptotes y=±xy = \pm x.

Example 5. A point is twice as far from (2,0)(2, 0) as from x=2x = -2. What conic?

(x2)2+y2=2x+2\sqrt{(x - 2)^2 + y^2} = 2 |x + 2|. So e=e = (distance to focus)/(distance to directrix) , wait, here the ratio is reversed. Let's set it: distance to point / distance to line = 1/2<11/2 < 1? No, the ratio is 22 (distance to focus is twice that to line), so this is a hyperbola with e=2e = 2.

Square: (x2)2+y2=4(x+2)2x24x+4+y2=4x2+16x+163x2+20x+12y2=0(x - 2)^2 + y^2 = 4(x + 2)^2 \Rightarrow x^2 - 4x + 4 + y^2 = 4 x^2 + 16 x + 16 \Rightarrow 3 x^2 + 20 x + 12 - y^2 = 0. This is a hyperbola.

Try it yourself

  1. Identify the conic x2+y2=9x^2 + y^2 = 9.
  2. Identify the conic y2=8xy^2 = 8 x.
  3. Identify the conic x216+y225=1\dfrac{x^2}{16} + \dfrac{y^2}{25} = 1. (Note: b>ab > a , vertical major axis.)
  4. Identify the conic x29y216=1\dfrac{x^2}{9} - \dfrac{y^2}{16} = 1.
  5. Find eccentricity of x236+y225=1\dfrac{x^2}{36} + \dfrac{y^2}{25} = 1.
  6. Find eccentricity of x216y29=1\dfrac{x^2}{16} - \dfrac{y^2}{9} = 1.
  7. A point moves so that its distance from (0,3)(0, 3) equals its distance from y=3y = -3. Find the equation.
  8. A point's distance from origin is half its distance from x=4x = 4. Find the conic.
  9. Identify 9x216y2=1449 x^2 - 16 y^2 = 144.
  10. What is the eccentricity of a circle?
  11. Convert 4x2+25y2=1004 x^2 + 25 y^2 = 100 to standard form and identify.
  12. Show that for a parabola, eccentricity is always 11.

Pitfalls / Tricks

  • Always reduce a general second-degree equation to one of the standard forms before identifying.
  • Check whether a2>b2a^2 > b^2 or a2<b2a^2 < b^2 in an ellipse , the major axis is along the larger one.
  • Hyperbola requires the difference of squares to equal 11, with opposite signs.
  • Insight. Eccentricity is the single number that distinguishes the four conics. It is the deepest unifying parameter in this chapter.

Practice quiz

Quick check on this topic.

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Quick check : Sections of a cone
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