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Geometric Progression (GP)

A bacterium splits in two every hour. After nn hours, the population has multiplied by 2n2^n. The population history 1,2,4,8,16,1, 2, 4, 8, 16, \dots is a geometric progression: each term is a fixed multiple of the previous. GPs describe every kind of exponential growth (and decay) , interest, radioactive substances, viral spread.

Definitions

A sequence a1,a2,a3,a_1, a_2, a_3, \dots is a geometric progression (GP) if the ratio an+1/ana_{n+1} / a_n is the same nonzero constant for every nn. That constant is the common ratio, denoted rr.

If the first term is aa, the GP is a, ar, ar2, ar3, a,\ ar,\ ar^2,\ ar^3,\ \dots

We assume a0a \ne 0. The ratio rr can be any nonzero real number , positive, negative, fractional. If r>1|r| > 1 the terms grow; if r<1|r| < 1 they shrink; if r=1r = -1 they alternate.

The nn-th term

an=arn1.\boxed{a_n = a r^{n - 1}.}

This is an exponential function of nn. GPs are exactly the sequences whose general term is exponential in nn.

Sum of the first nn terms

Let Sn=a+ar+ar2++arn1S_n = a + ar + ar^2 + \dots + ar^{n-1}. Multiply by rr: rSn=ar+ar2++arnr S_n = ar + ar^2 + \dots + ar^n. Subtract: SnrSn=aarnS_n - r S_n = a - ar^n, so (1r)Sn=a(1rn)(1 - r) S_n = a (1 - r^n), giving Sn=a1rn1r=arn1r1,r1.\boxed{S_n = a \cdot \frac{1 - r^n}{1 - r} = a \cdot \frac{r^n - 1}{r - 1}, \quad r \ne 1.}

If r=1r = 1, all terms equal aa, so Sn=naS_n = n a.

Infinite GP

If r<1|r| < 1, rn0r^n \to 0 as nn \to \infty. So S=limnSnS_\infty = \lim_{n \to \infty} S_n exists: S=a1r,r<1.\boxed{S_\infty = \frac{a}{1 - r}, \quad |r| < 1.}

If r1|r| \ge 1 (and a0a \ne 0), the infinite GP has no finite sum.

Properties

Three terms in GP. Often use a/r,a,ara/r, a, ar. Four terms: a/r3,a/r,ar,ar3a/r^3, a/r, ar, ar^3 (common ratio r2r^2).

Geometric mean property. Every middle term squared equals the product of its neighbours: an2=an1an+1a_n^2 = a_{n-1} a_{n+1}.

Multiplication of constants. Multiplying every term by a fixed nonzero constant gives another GP with the same ratio.

Worked examples

Example 1. Find the 77-th term of 3,6,12,24,3, 6, 12, 24, \dots

a=3,r=2a = 3, r = 2. a7=326=192a_7 = 3 \cdot 2^6 = 192.

Example 2. Find the sum of 2+6+18+54+2 + 6 + 18 + 54 + \dots to 1010 terms.

a=2,r=3,n=10a = 2, r = 3, n = 10. S10=2310131=3101=59048S_{10} = 2 \cdot \dfrac{3^{10} - 1}{3 - 1} = 3^{10} - 1 = 59048.

Example 3. Find k=012k\sum_{k=0}^{\infty} \dfrac{1}{2^k}.

This is a GP with a=1,r=1/2a = 1, r = 1/2. S=111/2=2S_\infty = \dfrac{1}{1 - 1/2} = 2.

Example 4. Three numbers are in GP. Their sum is 2121 and product is 216216. Find them.

Let them be a/r,a,ara/r, a, ar. Product: a3=216a=6a^3 = 216 \Rightarrow a = 6. Sum: 6/r+6+6r=216/r+6r=156+6r2=15r6r215r+6=02r25r+2=0r=26/r + 6 + 6r = 21 \Rightarrow 6/r + 6r = 15 \Rightarrow 6 + 6 r^2 = 15 r \Rightarrow 6 r^2 - 15 r + 6 = 0 \Rightarrow 2r^2 - 5r + 2 = 0 \Rightarrow r = 2 or r=1/2r = 1/2. Numbers: 3,6,123, 6, 12.

Example 5. Convert the repeating decimal 0.360.\overline{36} to a fraction.

0.36=0.363636=0.36+0.0036+0.000036+0.\overline{36} = 0.363636\dots = 0.36 + 0.0036 + 0.000036 + \dots This is a GP with a=0.36=36/100a = 0.36 = 36/100 and r=1/100r = 1/100. Sum =36/10011/100=36/10099/100=3699=411= \dfrac{36/100}{1 - 1/100} = \dfrac{36/100}{99/100} = \dfrac{36}{99} = \dfrac{4}{11}.

Try it yourself

  1. Find the 1010-th term of 5,10,20,40,5, 10, 20, 40, \dots
  2. Find the sum of 3+6+12+3 + 6 + 12 + \dots to 88 terms.
  3. Find the sum of the infinite GP 4,2,1,1/2,1/4,4, 2, 1, 1/2, 1/4, \dots
  4. Three numbers in GP have product 10001000 and sum 3535. Find them.
  5. The 33rd term of a GP is 2424, the 66th term is 192192. Find the 99th term.
  6. Express 0.1428570.\overline{142857} as a fraction. (Hint: it equals 1/71/7.)
  7. The sum of an infinite GP is 1515 and the sum of squares of its terms is 4545. Find the GP.
  8. How many terms of the GP 2,4,8,2, 4, 8, \dots sum to 20462046?
  9. If the sum of nn terms of a GP is SS and the product is PP, prove P2=(alast)nP^2 = (a \cdot \text{last})^n.
  10. Find three numbers in GP whose sum is 1313 and sum of squares is 9191.
  11. A ball is dropped from height 2020 m. After each bounce it rises to 4/54/5 of its previous height. Total distance travelled?
  12. Find the sum to nn terms: 7+77+777+7 + 77 + 777 + \dots (Hint: write as 79(101+1001+)\dfrac{7}{9}(10 - 1 + 100 - 1 + \dots).)

Pitfalls / Tricks

  • Use Sn=arn1r1S_n = a \dfrac{r^n - 1}{r - 1} when r>1r > 1 and Sn=a1rn1rS_n = a \dfrac{1 - r^n}{1 - r} when r<1|r| < 1 , keeps the sign clean.
  • Infinite GP sum requires r<1|r| < 1.
  • For three terms in GP, choose a/r,a,ara/r, a, ar to make sums and products simple.
  • Insight. A GP turns multiplication into addition (in the exponent). Whenever a problem has products or quotients of consecutive terms, GP is in the wings.

Practice quiz

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Quick check : Geometric Progression
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