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Chapter 12: Surface Areas and Volumes

So far we have measured flat shapes , circles, sectors, triangles, quadrilaterals. This chapter steps into three dimensions. Each solid is built up from flat pieces , a cylinder is two circles plus a rectangle wrapped around them, a cone is a circle plus a sector unrolled, a sphere is harder to unroll but obeys neat formulas of its own. The two main quantities we compute are surface area (the total flat area you would need to wrap the solid, measured in cm2^2) and volume (the space the solid fills, measured in cm3^3).

The chapter's signature problem is the combined solid: a cone on top of a cylinder, a hemisphere on the base of a cylinder, a frustum joining two circles of different sizes. To find the surface area or volume of a combination, you add the external surface areas and the full volumes of the pieces, taking care not to double-count surfaces that are hidden inside.

The applications are everywhere: an ice-cream cone with a scoop on top (cone + hemisphere), a water tanker (cylinder with hemispherical ends), a bucket (frustum), a tent (cone on cylinder), a child's toy. Board exam questions usually describe the solid in words, ask you to identify the parts, and then compute volume or surface area.

A key skill is converting volumes between shapes. If a metallic cone is melted and recast into a sphere, equating volumes gives the new radius. Hundreds of board problems use this idea.

What's inside

  • Cuboid and cube , formulas review.
  • Cylinder , curved + total surface area, volume.
  • Cone , slant height, lateral surface area, volume.
  • Sphere and hemisphere , surface area and volume.
  • Frustum of a cone , surface area, volume.
  • Combined solids , strategy and worked examples.

Key results / Formula card

For a cuboid with sides ,b,h\ell, b, h: V=bhV = \ell b h, surface area =2(b+bh+h)= 2(\ell b + bh + h\ell).

For a cube with side aa: V=a3V = a^3, surface area =6a2= 6 a^2.

For a cylinder with radius rr and height hh:

  • Curved surface area: 2πrh2\pi r h.
  • Total surface area: 2πrh+2πr2=2πr(h+r)2\pi r h + 2\pi r^2 = 2\pi r(h + r).
  • Volume: πr2h\pi r^2 h.

For a cone with radius rr, height hh, slant height =r2+h2\ell = \sqrt{r^2 + h^2}:

  • Curved surface area: πr\pi r \ell.
  • Total surface area: πr+πr2=πr(+r)\pi r \ell + \pi r^2 = \pi r(\ell + r).
  • Volume: (1/3)πr2h(1/3) \pi r^2 h.

For a sphere of radius rr:

  • Surface area: 4πr24\pi r^2.
  • Volume: (4/3)πr3(4/3) \pi r^3.

For a hemisphere of radius rr:

  • Curved surface area: 2πr22\pi r^2.
  • Total surface area: 3πr23\pi r^2.
  • Volume: (2/3)πr3(2/3) \pi r^3.

For a frustum of a cone with radii r1,r2r_1, r_2 and height hh, slant =h2+(r1r2)2\ell = \sqrt{h^2 + (r_1 - r_2)^2}:

  • Curved surface area: π(r1+r2)\pi(r_1 + r_2) \ell.
  • Total surface area: π(r1+r2)+πr12+πr22\pi(r_1 + r_2)\ell + \pi r_1^2 + \pi r_2^2.
  • Volume: (1/3)πh(r12+r22+r1r2)(1/3) \pi h (r_1^2 + r_2^2 + r_1 r_2).

Sub-topics

5 pages

Practice quiz

Answer the questions; explanations appear after each.

Quiz
Chapter 12 : Mixed practice
10 questions · pick the best answer
Q1

Volume of a cube of side 55 cm:

Q2

Surface area of a cube of side 77 cm:

Q3

Volume of a cylinder of radius 77 cm and height 1010 cm:

Q4

Slant height of a cone with r=6,h=8r = 6, h = 8:

Q5

Volume of a cone of radius 33 and height 44:

Q6

Surface area of a sphere of radius 77:

Q7

Volume of a hemisphere of radius rr:

Q8

Slant height formula for frustum:

Q9

Volume of a frustum with r1=4,r2=1,h=4r_1 = 4, r_2 = 1, h = 4:

Q10

When a solid is melted and recast, the conserved quantity is: