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Computing the missing side

The most useful skill from this chapter is also the simplest: given two sides of a right triangle, you can always find the third in one line.

Concept

Three cases.

  1. Find the hypotenuse given the two legs a,ba, b: c=a2+b2c = \sqrt{a^2 + b^2}.

  2. Find a leg given the hypotenuse cc and the other leg bb: a=c2b2a = \sqrt{c^2 - b^2}.

  3. (Trivial , for completeness.) Given hypotenuse cc and a leg bb, the other leg is also c2b2\sqrt{c^2 - b^2}.

Procedure.

  1. Sketch the triangle and label the right angle clearly. The hypotenuse is opposite the right angle and is always the longest side.
  2. Decide which of the three cases you are in.
  3. Write down the formula, square the known sides, do the arithmetic.
  4. Take a (positive) square root.

Common pitfalls.

  • Using cc as if it were a leg. The hypotenuse is always opposite the right angle.
  • Forgetting to square when applying the formula (writing c=a+bc = a + b , wrong).
  • Negative signs when subtracting under the root (means you misidentified which side is the hypotenuse).

Useful shortcut. If the two given sides match a Pythagorean triple (like 3,43, 4 or 5,125, 12), the answer is the third member of the triple (55 or 1313) , no calculation needed.

Decimal answers. Many right triangles don't have integer sides. Don't be alarmed. 2,5,50\sqrt{2}, \sqrt{5}, \sqrt{50} are perfectly valid lengths, even if they have non-terminating decimals.

Worked examples

Example 1. Find cc given a=6,b=8a = 6, b = 8.

  • c=36+64=100=10c = \sqrt{36 + 64} = \sqrt{100} = 10.

Example 2. Find the leg aa given c=13,b=5c = 13, b = 5.

  • a=16925=144=12a = \sqrt{169 - 25} = \sqrt{144} = 12.

Example 3. A right triangle has legs 11 and 22. Find the hypotenuse.

  • c=1+4=52.236c = \sqrt{1 + 4} = \sqrt{5} \approx 2.236.

Example 4. A ladder 55 m long leans against a wall. Its foot is 33 m from the wall. How high does the top touch?

  • Sketch: right triangle. Ladder is hypotenuse =5= 5. Distance from wall = leg =3= 3.
  • Height =259=16=4= \sqrt{25 - 9} = \sqrt{16} = 4 m.

Try it yourself

  1. Find the hypotenuse if legs are 99 and 1212.
  2. Find the leg if hypotenuse =17= 17 and the other leg is 88.
  3. A rectangle has sides 99 cm and 1212 cm. Find its diagonal.
  4. Find the diagonal of a square of side 1010 cm.
  5. A ladder leans against a wall reaching 44 m up; the foot is 33 m from the wall. Length of ladder?
  6. The hypotenuse of a right triangle is 1010. One leg is 66. Find the other.
  7. Find the hypotenuse if legs are 2\sqrt{2} and 7\sqrt{7}.
  8. Two trees are 66 m and 1111 m tall, standing 1212 m apart. The distance between their tops is?

Activity

Ladder safety. Building codes for ladders recommend a base-to-wall ratio of about 1:41 : 4 (so a ladder leaning a quarter of its length away from the wall is safe). For a 55 m ladder, the base should be 1.251.25 m from the wall. Use the theorem to find the height it reaches: 251.56254.84\sqrt{25 - 1.5625} \approx 4.84 m. Compare with the height you computed for a "33 m base" ladder. Safety is built on geometry.

Practice quiz

Quick check on this topic.

Quiz
Quick check : Computing the missing side
5 questions · pick the best answer
Q1

Legs 99 and 1212. Hypotenuse =

Q2

Hypotenuse 1717, leg 88. Other leg =

Q3

Rectangle 5×125 \times 12. Diagonal =

Q4

Legs 3\sqrt{3} and 11. Hypotenuse =

Q5

Hypotenuse 50\sqrt{50}, one leg 55. Other leg =