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Laws of exponents

When two powers share the same base, you should never multiply them out the long way. There are short rules that do the job in a single step. They were discovered by counting factors carefully and they hold for any base , counting numbers, fractions, even negative numbers.

Concept

Law 1 , Product of same bases. am⋅an=am+n\quad a^m \cdot a^n = a^{m+n}.

Why? ama^m has mm copies of aa, ana^n has nn copies; multiplying them places all of them in one row, m+nm+n in total. Example: 23⋅24=(2⋅2⋅2)(2⋅2⋅2⋅2)=27=1282^3 \cdot 2^4 = (2 \cdot 2 \cdot 2)(2 \cdot 2 \cdot 2 \cdot 2) = 2^7 = 128.

Law 2 , Quotient of same bases. aman=am−n\quad \dfrac{a^m}{a^n} = a^{m-n} (for a≠0a \ne 0).

In the quotient aman\frac{a^m}{a^n}, nn of the factors in the top cancel with the nn factors in the bottom. What remains is m−nm - n factors on top. Example: 5754=53=125\frac{5^7}{5^4} = 5^3 = 125.

Law 3 , Power of a power. (am)n=amn\quad (a^m)^n = a^{mn}.

(am)n(a^m)^n means "multiply ama^m by itself nn times", which gives n×mn \times m copies of aa. Example: (32)4=38(3^2)^4 = 3^8.

Law 4 , Power of a product. (ab)n=anbn\quad (ab)^n = a^n b^n.

Multiplying (ab)(ab) by itself nn times rearranges into nn copies of aa and nn copies of bb. Example: (2⋅5)3=103=1000(2 \cdot 5)^3 = 10^3 = 1000 and also 23⋅53=8⋅125=10002^3 \cdot 5^3 = 8 \cdot 125 = 1000. ✓

Law 5 , Power of a quotient. (ab)n=anbn\quad \left(\dfrac{a}{b}\right)^n = \dfrac{a^n}{b^n} (for b≠0b \ne 0).

Same idea as Law 4, but with division.

These five laws compose. If you see (23⋅54)2\left(\dfrac{2^3 \cdot 5}{4}\right)^2, you just use the laws step by step.

A common trap: the laws only combine same bases. The expression 23⋅342^3 \cdot 3^4 does not simplify to a single power , you have to either compute it as 8⋅81=6488 \cdot 81 = 648, or leave it as 23⋅342^3 \cdot 3^4. There is no rule am⋅bm=(ab)ma^m \cdot b^m = (ab)^m unless the exponents match (Law 4), and no rule for unequal bases.

Another trap: (a+b)n≠an+bn(a+b)^n \ne a^n + b^n in general. For example (1+2)2=9(1+2)^2 = 9 but 12+22=51^2 + 2^2 = 5.

Worked examples

Example 1. Simplify 34⋅353^4 \cdot 3^5.

  • Same base, add exponents: 34+5=393^{4+5} = 3^9.

Example 2. Simplify 28⋅2325\dfrac{2^8 \cdot 2^3}{2^5}.

  • Top: 28+3=2112^{8+3} = 2^{11}.
  • Divide: 211−5=26=642^{11-5} = 2^6 = 64.

Example 3. Simplify ((−2)3)2⋅(−2)4\big((-2)^3\big)^2 \cdot (-2)^4.

  • ((−2)3)2=(−2)6\big((-2)^3\big)^2 = (-2)^{6}.
  • Multiply: (−2)6⋅(−2)4=(−2)10=1024(-2)^{6} \cdot (-2)^4 = (-2)^{10} = 1024.

Example 4. Simplify (23⋅326)2\left(\dfrac{2^3 \cdot 3^2}{6}\right)^2.

  • 6=2⋅36 = 2 \cdot 3, so 23⋅326=23⋅322⋅3=22⋅31=12\dfrac{2^3 \cdot 3^2}{6} = \dfrac{2^3 \cdot 3^2}{2 \cdot 3} = 2^{2} \cdot 3^{1} = 12.
  • Square: 122=14412^2 = 144.

Try it yourself

  1. Simplify 56⋅535^6 \cdot 5^3 and write as a single power.
  2. Simplify 7975\dfrac{7^9}{7^5}.
  3. Simplify (23)4\big(2^3\big)^4 and find its value.
  4. Simplify (3⋅5)4\big(3 \cdot 5\big)^4 using a single base.
  5. Show (a2b3)4=a8b12(a^2 b^3)^4 = a^8 b^{12}.
  6. Without computing, decide which is greater: 2102^{10} or 10210^2.
  7. Simplify 215⋅310610\dfrac{2^{15} \cdot 3^{10}}{6^{10}}.
  8. Is 34⋅54=(15)43^4 \cdot 5^4 = (15)^4? Justify.

Activity / Insight

Powers of 22 chart. Write the powers of 22 from 20=12^0 = 1 up to 2202^{20}. Notice that 210=1024≈1032^{10} = 1024 \approx 10^3. This single approximation, 210≈1032^{10} \approx 10^3, is why "kilobyte" used to mean 10241024 bytes and why doubling something ten times multiplies it by roughly a thousand. From there, 220≈1062^{20} \approx 10^6 (a "mega") and 230≈1092^{30} \approx 10^9 (a "giga"). The laws of exponents and the laws of computing meet here.

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