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Patterns and conjectures

A conjecture is a guess based on evidence. Mathematicians often spot a pattern, guess what rule produces it, and then try to prove the guess. Sometimes a single counter-example destroys it; sometimes it survives every test and becomes a theorem.

Idea

Begin with small examples: 1=11 = 1 1+3=41 + 3 = 4 1+3+5=91 + 3 + 5 = 9 1+3+5+7=161 + 3 + 5 + 7 = 16

The right-hand sides are 1,4,9,16,1, 4, 9, 16, \dots , the squares. Conjecture: the sum of the first nn odd numbers is n2n^2. Test with n=5n = 5: 1+3+5+7+9=25=521+3+5+7+9 = 25 = 5^2 ✓. Test with n=6n = 6: 1+3+5+7+9+11=36=621+3+5+7+9+11 = 36 = 6^2 ✓. The pattern keeps holding. A clean visual proof: arrange nn rows of dots; each row adds one more odd-number worth of dots, building a square.

Another classic: 1=11 = 1 1+2=31 + 2 = 3 1+2+3=61 + 2 + 3 = 6 1+2+3+4=101 + 2 + 3 + 4 = 10 The RHS are 1,3,6,101, 3, 6, 10 , triangular numbers. Conjecture: 1+2++n=n(n+1)21 + 2 + \dots + n = \tfrac{n(n+1)}{2}. Check at n=5n = 5: 5×62=15=1+2+3+4+5\tfrac{5 \times 6}{2} = 15 = 1+2+3+4+5 ✓.

Method for working with patterns:

  1. Generate examples. Compute the first 4466 terms.
  2. Spot regularity. Look at differences, ratios, parities.
  3. Conjecture a formula. Test it on the next two terms.
  4. Try to justify. Why does it work? A picture, a small proof, an algebraic argument.

Even if you cannot prove your conjecture, the practice of carefully spotting and testing is valuable in itself.

Worked examples

Example 1. Consider 1,4,9,16,25,1, 4, 9, 16, 25, \dots. What is the nn-th term?

These are 12,22,32,1^2, 2^2, 3^2, \dots , the squares. So an=n2a_n = n^2.

Example 2. Spot the pattern: 2,5,10,17,26,2, 5, 10, 17, 26, \dots. Find the next two and a formula.

Differences are 3,5,7,9,3, 5, 7, 9, \dots , odd numbers, increasing by 22. So next differences 11,1311, 13, giving next two terms 26+11=3726+11=37 and 37+13=5037+13=50. Formula guess: an=n2+1a_n = n^2 + 1. Check: 1+1=2,4+1=5,9+1=101+1=2, 4+1=5, 9+1=10 ✓.

Example 3. Conjecture: "the sum of three consecutive numbers is always divisible by 33." Justify.

Three consecutive: n,n+1,n+2n, n+1, n+2. Sum =3n+3=3(n+1)= 3n + 3 = 3(n+1). Always a multiple of 33. ✓

Example 4. Consider triangular numbers Tn=1+2++nT_n = 1 + 2 + \dots + n. Show Tn+Tn+1=(n+1)2T_n + T_{n+1} = (n+1)^2.

Tn+Tn+1=n(n+1)2+(n+1)(n+2)2=(n+1)(n+n+2)2=(n+1)(2n+2)2=(n+1)2T_n + T_{n+1} = \tfrac{n(n+1)}{2} + \tfrac{(n+1)(n+2)}{2} = \tfrac{(n+1)(n + n + 2)}{2} = \tfrac{(n+1)(2n+2)}{2} = (n+1)^2. ✓

Try it yourself

  1. Find the next two terms of 1,8,27,64,1, 8, 27, 64, \dots. State the formula.
  2. Pattern: 1,3,7,15,31,1, 3, 7, 15, 31, \dots. Find a6a_6 and conjecture a formula.
  3. Compute 1+3+5+7+91 + 3 + 5 + 7 + 9. Is it a perfect square?
  4. Sum of first 2020 odd numbers , without adding them, what is it?
  5. Sum the first 1010 natural numbers. Use the formula.
  6. Is the sum of two triangular numbers always a square? (Try.)
  7. Conjecture: "the product of two consecutive numbers is always even." Justify.
  8. Find the pattern: 3,9,27,81,3, 9, 27, 81, \dots. What is the 77th term?

Activity

Pick three favourite patterns from this chapter. For each, write the first 55 terms, the rule, a small proof or justification. Make a "patterns poster" for your classroom.

Practice quiz

Quick check on this topic.

Quiz
Quick check : Patterns and conjectures
5 questions · pick the best answer
Q1

Next two terms of 1,8,27,64,1,8,27,64,\dots:

Q2

1+3+5+7+9=1+3+5+7+9=:

Q3

Sum of first 2020 odd numbers:

Q4

Sum of first 1010 natural numbers:

Q5

77th term of 3,9,27,81,3,9,27,81,\dots: