The distributive property
This is one of the most powerful rules in mathematics. It lets us swap a single multiplication for two , or two for one , depending on which form is easier.
Idea
The distributive property says:
a×(b+c)=a×b+a×c.
And similarly:
a×(b−c)=a×b−a×c.
You can picture it as a rectangle of width a and length b+c. Total area is a(b+c). Cut the rectangle vertically at b, and you have two rectangles of areas ab and ac. The two cuts must add up to the whole.
The rule works both ways:
- Expanding , 7×23=7×(20+3)=140+21=161.
- Factoring , 42+35=7×6+7×5=7×(6+5)=7×11=77.
Use expanding when you have a hard multiplication. Break the second factor into a sum of easy numbers (like 20+3 instead of 23) and multiply each.
Use factoring when you spot a common factor in a sum. It often turns a tedious problem into a one-step calculation.
The same rule works with three or more terms: a(b+c+d)=ab+ac+ad. And mixed signs: a(b−c+d)=ab−ac+ad.
Worked examples
Example 1. Use distribution to compute 6×102 mentally.
6×102=6×(100+2)=600+12=612.
Example 2. Use distribution backwards: 14×7+14×3.
Common factor is 14: 14×(7+3)=14×10=140.
Example 3. Compute 98×6 using a difference inside the bracket.
98=100−2, so 98×6=(100−2)×6=600−12=588.
Example 4. Simplify 5×(8+2−3) two ways.
By BODMAS: 5×(10−3)=5×7=35. By distribution: 5×8+5×2−5×3=40+10−15=35. Both give 35. ✓
Try it yourself
- Expand 4(6+9).
- Compute 7×99 using distribution.
- Compute 11×25+11×75 using distribution.
- Expand 9(10−2).
- Compute 12×13+12×7.
- Use the distributive law to simplify 25×16.
- Show that a(b+c+d)=ab+ac+ad holds for a=3, b=4, c=2, d=5.
- Find the missing number: 4×□+4×8=4×12.
Activity
Draw a 7×13 grid on graph paper. Count the unit squares in two ways: as one rectangle (= 91), and as two rectangles 7×10 and 7×3 joined side by side (= 70+21=91). Convince yourself the distributive law is just rectangle-cutting.