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The distributive property

This is one of the most powerful rules in mathematics. It lets us swap a single multiplication for two , or two for one , depending on which form is easier.

Idea

The distributive property says: a×(b+c)=a×b+a×c.a \times (b + c) = a \times b + a \times c. And similarly: a×(bc)=a×ba×c.a \times (b - c) = a \times b - a \times c.

You can picture it as a rectangle of width aa and length b+cb + c. Total area is a(b+c)a(b + c). Cut the rectangle vertically at bb, and you have two rectangles of areas abab and acac. The two cuts must add up to the whole.

The rule works both ways:

  • Expanding , 7×23=7×(20+3)=140+21=1617 \times 23 = 7 \times (20 + 3) = 140 + 21 = 161.
  • Factoring , 42+35=7×6+7×5=7×(6+5)=7×11=7742 + 35 = 7 \times 6 + 7 \times 5 = 7 \times (6 + 5) = 7 \times 11 = 77.

Use expanding when you have a hard multiplication. Break the second factor into a sum of easy numbers (like 20+320 + 3 instead of 2323) and multiply each.

Use factoring when you spot a common factor in a sum. It often turns a tedious problem into a one-step calculation.

The same rule works with three or more terms: a(b+c+d)=ab+ac+ada(b + c + d) = ab + ac + ad. And mixed signs: a(bc+d)=abac+ada(b - c + d) = ab - ac + ad.

Worked examples

Example 1. Use distribution to compute 6×1026 \times 102 mentally.

6×102=6×(100+2)=600+12=6126 \times 102 = 6 \times (100 + 2) = 600 + 12 = 612.

Example 2. Use distribution backwards: 14×7+14×314 \times 7 + 14 \times 3.

Common factor is 1414: 14×(7+3)=14×10=14014 \times (7 + 3) = 14 \times 10 = 140.

Example 3. Compute 98×698 \times 6 using a difference inside the bracket.

98=100298 = 100 - 2, so 98×6=(1002)×6=60012=58898 \times 6 = (100 - 2) \times 6 = 600 - 12 = 588.

Example 4. Simplify 5×(8+23)5 \times (8 + 2 - 3) two ways.

By BODMAS: 5×(103)=5×7=355 \times (10 - 3) = 5 \times 7 = 35. By distribution: 5×8+5×25×3=40+1015=355 \times 8 + 5 \times 2 - 5 \times 3 = 40 + 10 - 15 = 35. Both give 3535. ✓

Try it yourself

  1. Expand 4(6+9)4(6 + 9).
  2. Compute 7×997 \times 99 using distribution.
  3. Compute 11×25+11×7511 \times 25 + 11 \times 75 using distribution.
  4. Expand 9(102)9(10 - 2).
  5. Compute 12×13+12×712 \times 13 + 12 \times 7.
  6. Use the distributive law to simplify 25×1625 \times 16.
  7. Show that a(b+c+d)=ab+ac+ada(b + c + d) = ab + ac + ad holds for a=3a = 3, b=4b = 4, c=2c = 2, d=5d = 5.
  8. Find the missing number: 4×+4×8=4×124 \times \square + 4 \times 8 = 4 \times 12.

Activity

Draw a 7×137 \times 13 grid on graph paper. Count the unit squares in two ways: as one rectangle (= 9191), and as two rectangles 7×107 \times 10 and 7×37 \times 3 joined side by side (= 70+21=9170 + 21 = 91). Convince yourself the distributive law is just rectangle-cutting.

Practice quiz

Quick check on this topic.

Quiz
Quick check : The distributive property
5 questions · pick the best answer
Q1

Expand 4(6+9)4(6+9).

Q2

Compute 7×997\times 99 using distribution.

Q3

11×25+11×7511\times 25+11\times 75 equals:

Q4

25×1625\times 16 by distribution equals:

Q5

4×+4×8=4×124 \times \square + 4\times 8 = 4\times 12. Then \square is: